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secondary 3 | E Maths
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please help with this question asap. Thank youu!!
Date Posted: 3 years ago
Views: 653
PR is a chord of the circle.
Since PR passes through the centre O, PR is a diameter of the circle.
This means that PQRO is a semicircle.
∠PQR = 90°
(angle in a semicircle is a right angle)
PRST is a cyclic quadrilateral
∠PRS + ∠PTS = 180°
(Opposite angles of a cyclic quadrilateral
Or
Angles in opposite segments are supplementary)
So ∠PQR + ∠PRS + ∠PTS
= 90° + 180°
= 270°
Since PR passes through the centre O, PR is a diameter of the circle.
This means that PQRO is a semicircle.
∠PQR = 90°
(angle in a semicircle is a right angle)
PRST is a cyclic quadrilateral
∠PRS + ∠PTS = 180°
(Opposite angles of a cyclic quadrilateral
Or
Angles in opposite segments are supplementary)
So ∠PQR + ∠PRS + ∠PTS
= 90° + 180°
= 270°
See 1 Answer
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Hope this helps
Date Posted:
3 years ago
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