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secondary 2 | Maths
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Triscia
Triscia

secondary 2 chevron_right Maths chevron_right Singapore

Please help ASAP!! I really need it

Date Posted: 3 years ago
Views: 197
J
J
3 years ago
(x - 1)/(2x + 3) = y + 4

x - 1 = (y + 4)(2x + 3)

x - 1 = 2xy + 3y + 8x + 12

x - 2xy - 8x = 3y + 12 + 1

-7x - 2xy = 3y + 13

-x(7 + 2y) = 3y + 13

-x = (3y + 13)/(7 + 2y)

-x = (3y + 10.5 + 2.5)/(7 + 2y)

-x = (3/2)(2y + 7)/(7 + 2y) + 2.5/(2y + 7)

-x = 3/2 + 5 / (2(2y + 7))

x = - 3/2 - 5/(2(2y + 7))
J
J
3 years ago
Edited

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Abiraami
Abiraami's answer
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I hope you understand :)