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primary 5 | Maths
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Please help with C.
Figure 1 : 2 squares
Figure 2 : 3 squares
Figure 3 : 4 squares
Figure 4 : 5 squares
So for Figure 6, there are 7 squares.
So for figure 10, number of circles
= 10 x 10
= 100
Number of squares = 10 + 1 = 11
Total = 100 + 11 = 111
what we notice is that since
Squares = figure number x 1 + 1
Circles = figure number x figure number
Total = figure number x figure number + figure number x 1 + 1
= figure number x (figure number + 1) + 1
Eg. For figure 4,
Squares = 4 x 1 + 1 = 4 + 1 = 5
Circles = 4 x 4 = 16
Total = 4 x 4 + 4 x 1 + 1
= 4 x (4 + 1) + 1
= 4 x 5 + 1
= 20 + 1
= 21
So for 6481 total squares and circles,
6481 = figure number x (figure number + 1) + 1
Subtract 1 from both sides,
6480 = figure number x (figure number + 1)
Now 6480 = 80 x 81
So the answer is figure 80
(figure number) x (figure number + 1) = total - 1 = 6480,
Realise that the two numbers are very close. The product is very close to the product of squaring either number.
You can do a smart guess by finding the square root of 6480 with your calculator, and then taking the rounded down or rounded up whole number.
√6480 ≈ 80.4984472
From this we know that one of the numbers should be 80 (round down) and the other is 81 (round up)
80 x 81 = 6480
This is very close to (and in fact between)
80 x 80 = 6400
and
81 x 81 = 6561
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