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Hope this helps
Date Posted:
3 years ago
Thanks.
But I don't understand why 4/11 = 4/11 x 33 divide 1/5
Can help explain?
But I don't understand why 4/11 = 4/11 x 33 divide 1/5
Can help explain?
1/5 →33u {11/55 →33u}
4/11 → ? {20/55→?}
In this case, I changed all denominator to 55.
Common multiple of 5 and 11.
Therefore, we can say
11u→ 33
20u= 20u / 11u × 33 = 60.
...
...
Note: 4/11 is 4u of total 11u.
and 1/5 is 1u of total 5u.
Since total is the same, we made total to 55u.
Common multiple of 5 and 11.
4/11 → ? {20/55→?}
In this case, I changed all denominator to 55.
Common multiple of 5 and 11.
Therefore, we can say
11u→ 33
20u= 20u / 11u × 33 = 60.
...
...
Note: 4/11 is 4u of total 11u.
and 1/5 is 1u of total 5u.
Since total is the same, we made total to 55u.
Common multiple of 5 and 11.
If you can understand ..
1u —> 4
2u —> 8
3u —> 12
It is actually work this way
1u —> 4
2u = 2u/1u x 4 = 8
Therefore, if
A —-> B
C = C/A x B or C = C x B divide A
Now, we replace
A = 1/5
B= 33
C = 4/11
Then look we replace C = C/A x B or C = C x B divide A
4/11 = 4/11 x 33 divide 1/5
1u —> 4
2u —> 8
3u —> 12
It is actually work this way
1u —> 4
2u = 2u/1u x 4 = 8
Therefore, if
A —-> B
C = C/A x B or C = C x B divide A
Now, we replace
A = 1/5
B= 33
C = 4/11
Then look we replace C = C/A x B or C = C x B divide A
4/11 = 4/11 x 33 divide 1/5
Thanks a lot!