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secondary 3 | A Maths
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Date Posted: 3 years ago
Views: 284
sin 3A
= sin (2A + A)
= sin 2A cos A + cos 2A sin A
= (2 sin A cos A) cos A + (1 - 2 sin²A) sin A
= 2 sin A cos² A + sin A - 2 sin³ A
= 2 sin A (1 - sin² A) + sin A - 2 sin³ A
= 2 sin A - 2 sin³ A + sin A - 2 sin³ A
= 3 sin A - 4 sin³ A
(Shown)
= sin (2A + A)
= sin 2A cos A + cos 2A sin A
= (2 sin A cos A) cos A + (1 - 2 sin²A) sin A
= 2 sin A cos² A + sin A - 2 sin³ A
= 2 sin A (1 - sin² A) + sin A - 2 sin³ A
= 2 sin A - 2 sin³ A + sin A - 2 sin³ A
= 3 sin A - 4 sin³ A
(Shown)
See 1 Answer
done
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Hope this helps
Date Posted:
3 years ago
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