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primary 5 | Maths
| Angles & Geometry
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Pls help
Date Posted: 3 years ago
Views: 389
You should be able to find that the lengths of squares X, Y and Z are 6cm, 9cm and 12cm respectively.
Draw a straight line from the top left corner of square Y to the bottom right corner.
You have now divided the shaded area into two triangles.
The smaller triangle has a height equal to length of square Y (9cm).
It has a base equal to the difference between the length of square Y and X.
Difference in length of square X and Y
= 9cm - 6cm
= 3cm
Area of smaller triangle
= ½ x 3cm x 9cm
= ½ x 27cm²
= 13½ cm²
The bigger triangle also has a height equal to length of square Y (9cm).
It has a base equal to the length of square Z (12cm)
Area of bigger triangle
= ½ x 12cm x 9cm
= 6cm x 9cm
= 54cm²
Total area of shaded parts
= 54cm² + 13½ cm²
= 67½cm²
Draw a straight line from the top left corner of square Y to the bottom right corner.
You have now divided the shaded area into two triangles.
The smaller triangle has a height equal to length of square Y (9cm).
It has a base equal to the difference between the length of square Y and X.
Difference in length of square X and Y
= 9cm - 6cm
= 3cm
Area of smaller triangle
= ½ x 3cm x 9cm
= ½ x 27cm²
= 13½ cm²
The bigger triangle also has a height equal to length of square Y (9cm).
It has a base equal to the length of square Z (12cm)
Area of bigger triangle
= ½ x 12cm x 9cm
= 6cm x 9cm
= 54cm²
Total area of shaded parts
= 54cm² + 13½ cm²
= 67½cm²
See 1 Answer
done
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Draw an imaginary / dotted line from edge of square x to square y. Will make it easier for you to know the length and calculate
Date Posted:
3 years ago
Thanks
You are welcome
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