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I am not sure how to do it,
Date Posted: 4 years ago
Views: 248
If 3 - 5i is a root...
...so does 3 + 5i; they come in pairs (if you have used the quadratic formula to solve quadratic equations and obtained answers with square roots, you will notice that they come in opposite pairs)
Roots are 3 - 5i and 3 + 5i.
Sum of roots
= 3 - 5i + 3 + 5i
= 6
Product of roots
= (3 - 5i) (3 + 5i)
= 9 + 15i - 15i - 25i^2
= 9 - 25i^2
= 9 - 25 (-1)
= 34
Equation is
x^2 - (Sum)x + Product) = 0
x^2 - 6x + 34 = 0
where p = -6 and q = 34
...so does 3 + 5i; they come in pairs (if you have used the quadratic formula to solve quadratic equations and obtained answers with square roots, you will notice that they come in opposite pairs)
Roots are 3 - 5i and 3 + 5i.
Sum of roots
= 3 - 5i + 3 + 5i
= 6
Product of roots
= (3 - 5i) (3 + 5i)
= 9 + 15i - 15i - 25i^2
= 9 - 25i^2
= 9 - 25 (-1)
= 34
Equation is
x^2 - (Sum)x + Product) = 0
x^2 - 6x + 34 = 0
where p = -6 and q = 34
See 1 Answer
done
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-6 and 34
Date Posted:
4 years ago
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