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Primary 4 | Maths
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Date Posted: 3 years ago
Views: 344
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Let breadth (short) be b
Let length (long) be L
6b + 3L= 144
L = 3b
substitute L = 3b,
6b + 3(3b) = 144
9b = 144
b = 16
L = 3(16) = 48
Perimeter of 1 rectangle = 2b + 2L = 2(16) + 2(48) = 128cm
Let length (long) be L
6b + 3L= 144
L = 3b
substitute L = 3b,
6b + 3(3b) = 144
9b = 144
b = 16
L = 3(16) = 48
Perimeter of 1 rectangle = 2b + 2L = 2(16) + 2(48) = 128cm
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