Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 2 | Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Hello I recently solved this problem, and I would like to check if my answer is correct and if my presentation and reasoning is sound. Please correct and nitpick as much as you like as this is one of the first times where I actually managed to solve the problem. Thank you!
Date Posted: 3 years ago
Views: 233
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
if the condition is m>n and m,n must both be positive integers, then m=1, n=0 should not be valid solution because 0 is neither positive nor negative.
i am not sure if you can find a solution by calculation, but one possible method is solving by elimination.
(1+80n) must end with 1,
so sqrt(1+80n) must end with 1 or 9.
we list out possible values of sqrt(1+80n),
then work out corresponding values of m & n,
and eliminate invalid combinations until left with final answer.
smallest m x n should be 380.
i am not sure if you can find a solution by calculation, but one possible method is solving by elimination.
(1+80n) must end with 1,
so sqrt(1+80n) must end with 1 or 9.
we list out possible values of sqrt(1+80n),
then work out corresponding values of m & n,
and eliminate invalid combinations until left with final answer.
smallest m x n should be 380.
Date Posted:
3 years ago
360 Tutoring Program