Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Need help for part (ii). Thanks
Date Posted: 3 years ago
Views: 226
40 - (3 sin x + 4 cos x)^2
= 40 - [5 sin (x + taninv 4/3)]^2
For maximum,
5 sin (x + taninv 4/3) = 0
x + taninv 4/3 = 180, 360, ...
You should be getting the two answers you obtained.
You can always resubstitute your answers for validity.
The minimum case works when sin (x + taninv 4/3) is +- 1.
= 40 - [5 sin (x + taninv 4/3)]^2
For maximum,
5 sin (x + taninv 4/3) = 0
x + taninv 4/3 = 180, 360, ...
You should be getting the two answers you obtained.
You can always resubstitute your answers for validity.
The minimum case works when sin (x + taninv 4/3) is +- 1.
Ok. Thanks a lot
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Apologies. Here's the one with the R method
Date Posted:
3 years ago
Thanks s lot!
360 Tutoring Program