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secondary 3 | A Maths
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Date Posted: 3 years ago
Views: 173
If you square both equations, the resultant expressions will be identical. However, currently the expressions are not identical if you extend the curve beyond 2pi.
This is because sin (x/2) goes into the negative region from 2pi to 4pi. On the other hand, the square rooted expression will always have a positive value, so it cannot possibly be equal to sin (x/2) in that interval.
This is because sin (x/2) goes into the negative region from 2pi to 4pi. On the other hand, the square rooted expression will always have a positive value, so it cannot possibly be equal to sin (x/2) in that interval.
Oh ok. I understand. Thanks
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done
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Y1 and Y2 are equal for x =0,90,180,270 and 360.
Date Posted:
3 years ago
Thanks a lot
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