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secondary 3 | E Maths
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pls help!! thank you so much ^.^
Date Posted: 3 years ago
Views: 219
For the first part, consider the ∆XOP.
AP = 16cm (Radius of circle centre P)
AX = XP = 16/2 = 8cm (AX + XP = AP)
OP = 9cm (Radius of circle centre O)
∆XOP is a right angle triangle (Perpendicular bisector of a chord)
=>Angle APB = arccos 8/9
Or using the cosine rule, we can use ∆AOP,
Cos APB = (9² + 16² -9²)/(2(16)(9)) = 8/9
=> Angle APB = arccos (8/9)
For the second part
Angle AOD = 2Angle APB (angle at centre = 2 angle at circumference)
= 2arccos(8/9)
For the final part, we can make us of the formula RQ = arc length where R is the radius and Q is the angle in radians
9(2arccos(8/9) + 16(arccos(8/9)
Hope this helps.
AP = 16cm (Radius of circle centre P)
AX = XP = 16/2 = 8cm (AX + XP = AP)
OP = 9cm (Radius of circle centre O)
∆XOP is a right angle triangle (Perpendicular bisector of a chord)
=>Angle APB = arccos 8/9
Or using the cosine rule, we can use ∆AOP,
Cos APB = (9² + 16² -9²)/(2(16)(9)) = 8/9
=> Angle APB = arccos (8/9)
For the second part
Angle AOD = 2Angle APB (angle at centre = 2 angle at circumference)
= 2arccos(8/9)
For the final part, we can make us of the formula RQ = arc length where R is the radius and Q is the angle in radians
9(2arccos(8/9) + 16(arccos(8/9)
Hope this helps.
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Hope this helps!
Date Posted:
3 years ago
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