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primary 6 | Maths
| Measurement
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Date Posted: 4 years ago
Views: 289
X+y+z=320
X=z
By looking at the model, we should shift y so that starting line is at same position of other model bars. When we shift y, y will not be the same length as x and z as the gap is 30 but y only has extra 20. That area is missing, it is also difference between x or z and y.
Difference=30-20=10
Now we make all bars equal so we can find x.
3x=320+10=330
X=330÷3=110
Y=110-10=100
Ans:100
X=z
By looking at the model, we should shift y so that starting line is at same position of other model bars. When we shift y, y will not be the same length as x and z as the gap is 30 but y only has extra 20. That area is missing, it is also difference between x or z and y.
Difference=30-20=10
Now we make all bars equal so we can find x.
3x=320+10=330
X=330÷3=110
Y=110-10=100
Ans:100
Thank you!
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Date Posted:
4 years ago
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