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Question
secondary 3 | A Maths
4 Answers Below
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How do i do part iii
Date Posted: 3 years ago
Views: 178
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Using quadratic equation
Alpha plus beta =-b/a
Alpha plus beta =-b/a
Date Posted:
3 years ago
The eqn is wrong for the straight line
You correct me I believe you can do
I did but the thing is when I tried to prove it my answer does not match
I keep ending up with b(0,0)
The first part?
The first part I got 1/2 same as you
Show me your workout
I knew I meant mistake for b
Should be
2 -6/5
Should be
2 -6/5
Where?
Refer to the new answer the rest you might need to correct it
Ok thanks
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Use formula
Mid point =( (Xa+Xb)/2, (ya+yb)/2)
Perpendicular Gradient is =1/(-1) of the gradient
Find equation then sub
Center
(3/2, -1/2)
Must practise Orelse exam don’t know how to do
Mid point =( (Xa+Xb)/2, (ya+yb)/2)
Perpendicular Gradient is =1/(-1) of the gradient
Find equation then sub
Center
(3/2, -1/2)
Must practise Orelse exam don’t know how to do
Date Posted:
3 years ago
done
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I keep getting this
Date Posted:
3 years ago
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This is the B , x value I made mistake
Date Posted:
3 years ago
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