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secondary 4 | A Maths
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How do i solve this qn?
Date Posted: 3 years ago
Views: 222
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Form equation
(0,0) is one solution
(2^(1/3) , 2^(4/3)) is another
Mid point formula
(2^(-2/3), 2^(1/3)) let (a,b)
Gradient -1/(2)
Therefore -1/2= (y-b)/(x-a)
(0,0) is one solution
(2^(1/3) , 2^(4/3)) is another
Mid point formula
(2^(-2/3), 2^(1/3)) let (a,b)
Gradient -1/(2)
Therefore -1/2= (y-b)/(x-a)
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