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primary 6 | Maths
| Algebra
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Help for Q9b please. I’m not too sure about the topic but ok. Thanks for the help! :D
Date Posted: 4 years ago
Views: 330
This is an unchanged difference question.
The difference in their ages is always the same, 8 years. As one person grows a year older, so will the other person.
Since we are looking for the time when Kit was 3 times as old as Jane,
Kit's age would have been 3 units, and Jane's 1 unit
Difference = 3 - 1 = 2 units
So 2 units = 8 years
1 unit = 8 years ÷ 2 = 4 years
So this means Jane was 4 years old back then.
Since she is 10 years old now,
10 - 4 = 6
It was 6 years ago.
The difference in their ages is always the same, 8 years. As one person grows a year older, so will the other person.
Since we are looking for the time when Kit was 3 times as old as Jane,
Kit's age would have been 3 units, and Jane's 1 unit
Difference = 3 - 1 = 2 units
So 2 units = 8 years
1 unit = 8 years ÷ 2 = 4 years
So this means Jane was 4 years old back then.
Since she is 10 years old now,
10 - 4 = 6
It was 6 years ago.
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Date Posted:
4 years ago
I dont think he or she will understand bcos P6 dont learn the inner part of algebra
The equation is formed as it was predicted that kit’s age will be thrice of jane’s age around x years ago.
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x is jane’s age when kit was three times her age
Date Posted:
4 years ago
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