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primary 6 | Maths
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Pls help me for both the qus
Q 21)
You can start by looking at triangle KLM, which is an equilateral triangle. So each angle at K, L and M is 60*.
Now, you may focus on triangle LNM. To find the angle at N, simply take 180* (sum of all angles in the triangle) - 60* (at M) - 38* (at L) = 82*
Angle JNO is also equal to 82*, (adjacent angles). To find angle OJN which the question asks, take 180* (from triangle OJN), - 58* (at O) - 82*, to get 40* (the answer).
Q22)
In a parallelogram, sum of all internal angles = 360*. And opposite angles are equal, meaning U=W (in this case, 114*). So, V = 360* - (114* X 2) = 66*.
So the entire angle opposite to V is 66*. (as you have drawn using your pencil). The entire point including 160*, 66* and angle UXZ, is = 360*.
So to find angle UXZ, simply take 360*, and minus 160* and 66*, to get 134*. (answer)
Hope this helps!
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