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secondary 3 | A Maths
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secondary 3 chevron_right A Maths chevron_right Singapore

need help with this qn, pls explain too :)

Date Posted: 3 years ago
Views: 180

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
An idea
LockB
LockB
3 years ago
sorry i dont really understand the diagram for part b(ii) and (iii), can you explain to me again? thx :)
for b(ii) i dont really understand what is equidistant and for b(iii) i dont understand why is it perpendicular
Eric Nicholas K
Eric Nicholas K
3 years ago
Ok, remind me to write again later as I might forget

Idea is to identify the keywords “due north/east/south/west” and “on a bearing of”.

If A is “due north” of B, for example, then A is directly “above” B, on a bearing of 000.

If A is “due west” of B, then A is to the left of B, on a bearing of 270.

And so on.

If a point C is equidistant from A and B, it means that the distance from C to A is the same as the distance from C to B (equidistant = equal distance).

For shortest distance, imagine you are in school in your classroom. Your teacher calls you out to go to the whiteboard. You walk straight ahead to the whiteboard at right angles and not at an angle to the whiteboard. Think why is this usually the case. That is, why you chose a path at right angles than at an angle.
Eric Nicholas K
Eric Nicholas K
3 years ago
Re-writing now
LockB
LockB
3 years ago
thx :)
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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
Supplement for b(ii) and b(iii)