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secondary 3 | A Maths
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Pls help Mr. Eric. I tried so hard. Somehow I am missing the link
Date Posted: 3 years ago
Views: 172
Attempting
@Mr. Eric,How to find eqn of perpendicular bisector in 2 different ways? I usually find gradient and midpoint to get the eqn. A question asks for an alternate way. Pls enlighten me. Thanks a lot
You have the question? Usually I do by midpoint and gradient only.
A circle passes through the points A(0,-3) and B(2,-1). The center of the circle lies on the line 2x+y=0. Find the equation of the perpendicular bisector of AB using 2 different methods
and the equation of the circle.
and the equation of the circle.
I suspect we have to join (0, 3) to (2, 1), draw a perpendicular bisector cutting the centre of the circle and do the Pythagoras Theorem like I did earlier.
I thought about it. We have hypotenuse as r and another length ( half of the line). But no info about the vertical line which is only a part of radius
Or shall skip trying the alternative method and just stick to the usual method?
I suppose the second method is to “randomly” plot points C on a graph paper in which CA = CB, then connect them and then find from the graph paper.
I guess, gradient - midpoint is efficient . So I just don’t attempt that part of the qn?
You can just say “graphical method” for the other approach.
We stick to bisectors for calculation.
We stick to bisectors for calculation.
Ok. Sure. Great idea
Thanks a lot for all the guidance
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done
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Part a
Date Posted:
3 years ago
Brilliant !! Thanks a ton
done
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Part b and part c
Date Posted:
3 years ago
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