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Question
primary 6 | Maths
| Geometry
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Pls help. Thk u
Date Posted: 3 years ago
Views: 410
Very simple.
AB = BC = CD = AD (sides of the same square)
AB = BE = AE (sides of the same equilateral triangle)
Since AB = AD and AB = AE,
AD = AE
So triangle AED is isosceles.
∠ AED = ∠ ADE
(base angles of isosceles triangle AED, where AD = AE)
∠AED = (180° - 30°)/2
= 75°
AB = BC = CD = AD (sides of the same square)
AB = BE = AE (sides of the same equilateral triangle)
Since AB = AD and AB = AE,
AD = AE
So triangle AED is isosceles.
∠ AED = ∠ ADE
(base angles of isosceles triangle AED, where AD = AE)
∠AED = (180° - 30°)/2
= 75°
See 1 Answer
Thank u very much.
75° actually.
Anis, you can refer to my comments under the main comments section
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