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secondary 3 | A Maths
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Help Maximus Boo! Anyone can contribute an answer, even non-tutors.
Someone help with part (2,3 and 4) pls. Help would be greatly appreciated!
For part ii, you are required to find k value for 3 solutions. The only point the graph will have 3 solutions (cutting x axis) is below the turning point, where the solutions are the graph going up to the turning point, the graph going down from the turning point, and the right hand side of the parabola going infinity. Therefore you must shift the graph downwards by less than the x value of the turning point, and that is your k.
For 2 solutions, you have only one point where it gives 2 solutions, which is when the turning point touches x axis. This give the solutions at the turning point and the right hand side of the parabola. Therefore the value of k is the x value of the turning point.
For 1 solution, you have two ranges. The original graph already have one solution, which is the cutting point of the right hand side of the parabola. The next range will be the right side towards x=5, where it is above the turning point. Therefore the first range of k is k=0, and k more than the x value of the turning point
Hope it helps!
Thanks for detailed answer too!