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secondary 3 | A Maths
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Pls help with q7. Tysm!!
Date Posted: 7 years ago
Views: 333
Few points to take note. Firstly, you might have forgotten to put the gradient value on your linear law expression at
1/y=x^2+3.5. Otherwise, you got the right expression
Second note is that you can just get the inverse of the right hand side of the equation and you will the the equation in terms of y
1/y = 5/6 x^2 + 3.5
y=1(5/6 x^2+3.5)
You can then rearrange to make it in a simpler form. Otherwise, youre there already!
1/y=x^2+3.5. Otherwise, you got the right expression
Second note is that you can just get the inverse of the right hand side of the equation and you will the the equation in terms of y
1/y = 5/6 x^2 + 3.5
y=1(5/6 x^2+3.5)
You can then rearrange to make it in a simpler form. Otherwise, youre there already!
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Hi friend,
Any complicated question can be divided into a few simple questions.
come on and you can make it!
Please let me know if you have further question.
Teacher Xin Yao
Any complicated question can be divided into a few simple questions.
come on and you can make it!
Please let me know if you have further question.
Teacher Xin Yao
Date Posted:
7 years ago
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