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Hope this helps
Date Posted:
4 years ago
Thank you.
But how do you get 180-30, where do the 30 comes from? Why do we need to divide 150 by 2?
But how do you get 180-30, where do the 30 comes from? Why do we need to divide 150 by 2?
Realize the triangle PSV is isosceles triangle. Angle PSV = 30. Therefore, the other two angle for isosceles triangle is 150÷2 =75°
FYI, SR=PS as there are square for PQRS.
FYI, SR=PS as there are square for PQRS.
Yes. PS = SR (sides of the same square)
But SR = SU
(sides of the same equilateral triangle)
Therefore PS = SU
So triangle PSU is isosceles. And ∠SUP = ∠SPU
∠PSU =∠PSR (one of the square's right angles) - ∠USR(one of the angles of the equilateral triangle)
= 90° - 60°
= 30°
∠SUP + ∠SPU
= 180° - ∠PSU (angle sum of triangle PSU is 180°)
= 180° - 30°
= 150°
Since ∠SUP = ∠SPU,
2 ∠SPU = 150°
∠SPU = 150° ÷ 2 = 75°
Presenting as (180° - 30°)/2 is just combining these into 1 step.
But SR = SU
(sides of the same equilateral triangle)
Therefore PS = SU
So triangle PSU is isosceles. And ∠SUP = ∠SPU
∠PSU =∠PSR (one of the square's right angles) - ∠USR(one of the angles of the equilateral triangle)
= 90° - 60°
= 30°
∠SUP + ∠SPU
= 180° - ∠PSU (angle sum of triangle PSU is 180°)
= 180° - 30°
= 150°
Since ∠SUP = ∠SPU,
2 ∠SPU = 150°
∠SPU = 150° ÷ 2 = 75°
Presenting as (180° - 30°)/2 is just combining these into 1 step.
Each of the sides of the equilateral triangle are equal to each side of the square.
As for why ∠RPS is 45°, realise that ∆PSR is isosceles since PS = SR (sides of the same square).
So ∠RPS = ∠PRS (base angles of isosceles triangle)
Since ∠PSR = 90° , (all 4 angles of a square are right angles)
∠RPS + ∠PRS = 180° - ∠PSR (angle sum of triangle PSR)
= 180° - 90°
= 90°
Since ∠RPS = ∠PRS,
2 ∠RPS = 90°
∠RPS = 90° ÷ 2 = 45°
As for why ∠RPS is 45°, realise that ∆PSR is isosceles since PS = SR (sides of the same square).
So ∠RPS = ∠PRS (base angles of isosceles triangle)
Since ∠PSR = 90° , (all 4 angles of a square are right angles)
∠RPS + ∠PRS = 180° - ∠PSR (angle sum of triangle PSR)
= 180° - 90°
= 90°
Since ∠RPS = ∠PRS,
2 ∠RPS = 90°
∠RPS = 90° ÷ 2 = 45°
Noted. Thank you so much.
Edited the first comment for more details.
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Hope this is clearer :)
Date Posted:
4 years ago