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secondary 3 | A Maths
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Hi. Pls help me with this qn. Thanks
Date Posted: 3 years ago
Views: 184
since the equation is parallel to the line, both lines have the same gradient
to find the equation sub m=-2 and (0,1) to y=mx+c
to find the equation sub m=-2 and (0,1) to y=mx+c
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done
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clear
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here's the answer
Date Posted:
3 years ago
Thank you
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