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Question
primary 6 | Maths
3 Answers Below
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Thanks much if someone who can lend me a helping hand!
Date Posted: 3 years ago
Views: 306
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Area of large quadrant + area of small quadrant - area of rectangle
= (pi x 14 x 14)/4 + (pi x 10 x 10)/4 - (10 x 14)
= (pi x 14 x 14)/4 + (pi x 10 x 10)/4 - (10 x 14)
Won't you be double counting the shaded area in the rectangle then?
We are double counting the intersection of the two quadrants, then minus one copy via the rectangle. Left with exactly one copy.
Using your diagram, my answer translates to
(A+B+C) + (B+D) - (B+C+D) = A+B
(A+B+C) + (B+D) - (B+C+D) = A+B
done
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Hope this helps
Date Posted:
3 years ago
Whenever you see such questions and unable to come up with any solutions, just go ahead and calculate the area of the quadrants to earn some working marks
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