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secondary 4 | A Maths
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I’m not sure how to do this question. Would appreciate detailed worked solution asap. Thanks!!
Date Posted: 4 years ago
Views: 250
Good afternoon Cheryl! I type them here.
For an angle with a basic value of x, where x is an acute angle, the actual angles are
x, if it is in the first quad
180 - x, if it is in the second quad
180 + x, if it is in the third quad
360 - x, if it is in the second quad
230 is in the third quad, so its basic angle is given by
180 + x = 230
x = 50
All the possible angles for B are
x = 50
180 - x = 130
180 + x = 230
360 - x = 310
Similarly for the second part,
320 is in the fourth quad, so its basic angle is given by
360 - x = 320
x = 40
All the possible angles for B are
x = 40
180 - x = 140
180 + x = 220
360 - x = 320
For an angle with a basic value of x, where x is an acute angle, the actual angles are
x, if it is in the first quad
180 - x, if it is in the second quad
180 + x, if it is in the third quad
360 - x, if it is in the second quad
230 is in the third quad, so its basic angle is given by
180 + x = 230
x = 50
All the possible angles for B are
x = 50
180 - x = 130
180 + x = 230
360 - x = 310
Similarly for the second part,
320 is in the fourth quad, so its basic angle is given by
360 - x = 320
x = 40
All the possible angles for B are
x = 40
180 - x = 140
180 + x = 220
360 - x = 320
I will present them in a diagram format at a later time if no one else has responded, you need more explanation and I can still remember.
Thank u!!
See 1 Answer
done
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Apply part (i) to part (ii) too. Explanation is a bit messy but hope tt helps :)
Date Posted:
4 years ago
Actually you hit the nail perfectly with the explanation. That is the idea.
Thank u!!!
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