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primary 6 | Maths
| Percentage
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Date Posted: 3 years ago
Views: 207
With each 25 m roll, number of 110 cm pieces possible
= 2500 / 110, rounded down
= 22.7272727..., rounded down
= 22
For 200 pieces altogether, number of rolls needed
= 200/22, rounded up
= 9.090909..., rounded up
= 10
Assume the remaining unused ribbons cannot be joined together to form full 110 cm pieces.
= 2500 / 110, rounded down
= 22.7272727..., rounded down
= 22
For 200 pieces altogether, number of rolls needed
= 200/22, rounded up
= 9.090909..., rounded up
= 10
Assume the remaining unused ribbons cannot be joined together to form full 110 cm pieces.
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Hope this helps
Date Posted:
3 years ago
Hi can you help me with my question?
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