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secondary 3 | E Maths
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Pls help me with part b.
Date Posted: 3 years ago
Views: 186
Cost of p oranges is q cents.
Cost of 1 orange
= Cost of number of oranges ÷ number of oranges
Based on the info,
Cost of 1 orange
= q cents / p
= q/p cents
Cost of 1 orange
= Cost of number of oranges ÷ number of oranges
Based on the info,
Cost of 1 orange
= q cents / p
= q/p cents
Nate has r dollars.
r dollars = r x 100 cents
(since 1 dollar = 100 cents)
= 100r cents
Number of oranges Nate can buy
= 100r cents ÷ p/q cents per orange
= 100r ÷ p/q
= 100r x q/p
= 100qr / p
r dollars = r x 100 cents
(since 1 dollar = 100 cents)
= 100r cents
Number of oranges Nate can buy
= 100r cents ÷ p/q cents per orange
= 100r ÷ p/q
= 100r x q/p
= 100qr / p
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