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Question
primary 6 | Maths
| Data Analysis
One Answer Below
This question need another answer.
The answer is 64 cm sq. However, I need a clear explanation on how to get the answer as I only get 56 cm sq.
Area of whole figure is 128 cm2.
Area of the 4 identical large squares, without any overlapping
= 128 + 4 x 2 x 2
= 128 + 16
= 144 cm2
Area of each large square is 36 cm2.
Length of each square is 6 cm.
I got 56 cm as my perimeter as (4 + 6 + 4) x 4 = 56..
I am pretty sure that the given answer, 64, counts the middle square as well, and I disagree with the answer. That section of the figure should not count as the perimeter of the object only counts the outer surrounding of the figure and does not include the perimeter of the missing square as well.
Without mentioning carefully, I would take "perimeter" as only the "external" perimeter of the figure.
This is the same as what is being used by the syllabus. Basically the outer edge.
Perhaps it is included as it is exposed to the outside.
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