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primary 6 | Maths
| Algebra
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i need help for both qn
Date Posted: 3 years ago
Views: 315
Multiples of 5 between 40 and 50: 40, 45, 50. Since there are 3 extra children, possible number of children are :
43, 48, 53 (reject 53 since >50)
Multiple of 6 between 40 and 50 : 42, 48
48 - 5 = 43 (minus 5 since there will be 5 short)
There are 43 children at the party.
second question:
a)Total of excess and shortage = 12+24 = 36
There are 36 pupils
b)No. of sweets = (36 x3) + 12 = 120
Note : imagine the children in the classroom. Mrs Ang goes round giving each pupil one sweet at a time. When she is finished giving each pupil 3 sweets, she has 12 left. She tries to go one more round. When she has given away the 12 sweets, there are 24 pupils that did not get the 4th sweet.
43, 48, 53 (reject 53 since >50)
Multiple of 6 between 40 and 50 : 42, 48
48 - 5 = 43 (minus 5 since there will be 5 short)
There are 43 children at the party.
second question:
a)Total of excess and shortage = 12+24 = 36
There are 36 pupils
b)No. of sweets = (36 x3) + 12 = 120
Note : imagine the children in the classroom. Mrs Ang goes round giving each pupil one sweet at a time. When she is finished giving each pupil 3 sweets, she has 12 left. She tries to go one more round. When she has given away the 12 sweets, there are 24 pupils that did not get the 4th sweet.
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