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secondary 2 | Maths
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Hi need help with A and B
Since ABCD is a rhombus, its diagonals meet at the exact centre of the rhombus, or the midpoints of each diagonal.
So, length of AF
= Half the length of AC
= 1/2 x 14
= 7 cm
Also, the diagonals meet at right angles.
AFB = 90
CAB = FAB = ACD = 18 (alternate angles)
y
= 180 - 90 - 18
= 72
Since AB = BC, triangle ABC is isosceles.
ACB = 18
BCD = 18 + 18 = 36
x
= BCD
= 36 (alternate angles)
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