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Hope this helps
Date Posted:
3 years ago
Another way :
You can see each set as a triangle that is half of a parallelogram.
Put two triangles together to get the parallelogram and you can form rows of circles.
Eg. First set
If you join two identical triangles together you get :
○○○/○
○○/○○
○/○○○
This is a parallelogram with 3 rows of 4 circles. Total circles = 3 x 4 = 12
First set is only half of that
= 3 x 4 ÷ 2
= 12 ÷ 2
= 6
Likewise for the rest,
Second set = 4 x 5 ÷ 2 = 20 ÷ 2 = 10
Third set = 5 x 6 ÷ 2 = 30 ÷ 2 = 15
The number of circles per row is always 1 more than the number of rows.
The number of rows is always 2 more than the set number.
So for 10th set,
Number of rows = 10 + 2 = 12
Number of circles per row = 12 + 1 = 13
Total
= 12 x 13 ÷ 2
= 78
For 35th set,
Number of rows = 35 + 2 = 37
Number of circles per row = 37 + 1 = 38
Total
= 37 x 38 ÷ 2
= 703
You can see each set as a triangle that is half of a parallelogram.
Put two triangles together to get the parallelogram and you can form rows of circles.
Eg. First set
If you join two identical triangles together you get :
○○○/○
○○/○○
○/○○○
This is a parallelogram with 3 rows of 4 circles. Total circles = 3 x 4 = 12
First set is only half of that
= 3 x 4 ÷ 2
= 12 ÷ 2
= 6
Likewise for the rest,
Second set = 4 x 5 ÷ 2 = 20 ÷ 2 = 10
Third set = 5 x 6 ÷ 2 = 30 ÷ 2 = 15
The number of circles per row is always 1 more than the number of rows.
The number of rows is always 2 more than the set number.
So for 10th set,
Number of rows = 10 + 2 = 12
Number of circles per row = 12 + 1 = 13
Total
= 12 x 13 ÷ 2
= 78
For 35th set,
Number of rows = 35 + 2 = 37
Number of circles per row = 37 + 1 = 38
Total
= 37 x 38 ÷ 2
= 703
The last row for 35th set has 37 circles since the pattern starts from 3 circles in the first set.
Yes. Forgot to add 2 on 35...
Working = 37x38 /2 .......
Working = 37x38 /2 .......
Thank you v much !
Thank you
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Correction: Answer for b)
Date Posted:
3 years ago