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secondary 4 | E Maths
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Please help me with ques 5
Thank youu!!
Date Posted: 3 years ago
Views: 224
Two patterns to consider.
One of which goes...
4, 9, 14, 19, ...
where the constant difference is +5 and the "zero"th term is 4 - 5 = -1 so its nth term is
5n - 1.
--------------------------------------------------------
The other goes....
20, 40, 60, 80, ...
where the constant difference is +20 and the "zero"th term is 20 - 20 = 0 so its nth term is
20n.
All other aspects of the pattern in T remain unchanged.
--------------------------------------------------------
Tn must be
(5n - 1)^2 + 20n
which simplifies to
25n^2 - 10n + 1 + 20n
= 25n^2 + 10n + 1
= (5n + 1) (5n + 1)
= (5n + 1)^2
This is a perfect square, but I strongly disagree with the "odd perfect square" stipulation.
One of which goes...
4, 9, 14, 19, ...
where the constant difference is +5 and the "zero"th term is 4 - 5 = -1 so its nth term is
5n - 1.
--------------------------------------------------------
The other goes....
20, 40, 60, 80, ...
where the constant difference is +20 and the "zero"th term is 20 - 20 = 0 so its nth term is
20n.
All other aspects of the pattern in T remain unchanged.
--------------------------------------------------------
Tn must be
(5n - 1)^2 + 20n
which simplifies to
25n^2 - 10n + 1 + 20n
= 25n^2 + 10n + 1
= (5n + 1) (5n + 1)
= (5n + 1)^2
This is a perfect square, but I strongly disagree with the "odd perfect square" stipulation.
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Identify the general equation solve for arithmetic progression then simplify and factorise
Date Posted:
3 years ago
Do take note that secondary school students are NOT exposed to the phrase "arithmetic progression" yet.
You need to explain using secondary school phrases.
You need to explain using secondary school phrases.
Thanks for the advice Eric, will take note
The working is clear enough. It's good to expose the student to what an AP is. It's always good to have prior knowledge. No point restricting learning to levels.
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I hope you are able to understand from this solution, and I hope I can get feedback on how I can improve my help! :)
Date Posted:
3 years ago
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