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primary 6 | Maths
| Data Analysis
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Date Posted: 4 years ago
Views: 504
Let make Jane money = $60 units days (20 and 30 common multiple)
Let number of day = u
1) When Jane spend $20 each day.
It take 3u x $20 to spend all the money.
So Claire will be 3u x $30 = $90u + 100
2) When Jane spend $30 each day.
It take 2u x $30 to spend all the money.
So Claire 2u x $20 = $40u + $600.
Therefore, Claire's total money are same.
90u + 100 = 40u +600
50u = 500
1u = 10
Total for Claire
= 40u + 600
=[40x10] +600
=$1000.
--or--
= 90u +100
= [90 x 10] + 100
= $ 1000.
Hope this helps
Let number of day = u
1) When Jane spend $20 each day.
It take 3u x $20 to spend all the money.
So Claire will be 3u x $30 = $90u + 100
2) When Jane spend $30 each day.
It take 2u x $30 to spend all the money.
So Claire 2u x $20 = $40u + $600.
Therefore, Claire's total money are same.
90u + 100 = 40u +600
50u = 500
1u = 10
Total for Claire
= 40u + 600
=[40x10] +600
=$1000.
--or--
= 90u +100
= [90 x 10] + 100
= $ 1000.
Hope this helps
See 1 Answer
done
2 Upvotes
clear 0 Downvotes
Hope this helps.
FYI, Jane's money = $600.
FYI, Jane's money = $600.
Date Posted:
4 years ago
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