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junior college 2 | H2 Maths
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Hello! Can someone please help me here? I don’t understand the phrasing of the question so i can’t write anything down at all except 2(P +R)= Q.... Thank you!!!
Date Posted: 3 years ago
Views: 449
You've misinterpreted. It should be P + R = 2Q
From a), since $9600 more profit is earned from builder R than P, and the profit per brick is $3,
Then profit from builder P = $3P
Profit from builder R = $3R
So $3R - $3P = $9600
3R - 3P = 9600
R - P = 3200
And given that the total number of bricks ordered is 30000,
Then P + Q + R = 30000
Then profit from builder P = $3P
Profit from builder R = $3R
So $3R - $3P = $9600
3R - 3P = 9600
R - P = 3200
And given that the total number of bricks ordered is 30000,
Then P + Q + R = 30000
Good evening Sonia! Looking at the questions now.
So you have 3 equations :
P+R = 2Q ①
P+Q+R = 30000 ②
R-P = 3200 ③
Where P,Q,R are the respective number of bricks ordered from each builder.
Solve for these (using gc or manual),
P = 8400, Q = 10000, R = 11600
P+R = 2Q ①
P+Q+R = 30000 ②
R-P = 3200 ③
Where P,Q,R are the respective number of bricks ordered from each builder.
Solve for these (using gc or manual),
P = 8400, Q = 10000, R = 11600
It’s 3200, not 2300
Sonia, you should get
P = 8400
Q = 10000
R = 11600
Will look at part ii later
Sonia, you should get
P = 8400
Q = 10000
R = 11600
Will look at part ii later
You're fast arent you? Was still editing
b)
We are left with these 2 equations since info from part a) is not to be used.
P+R = 2Q ①
P+Q+R = 30000 ②
Sub ① into ②,
2Q + Q = 30000
3Q = 30000
Q = 10000
Then P + R = 30000 - 10000 = 20000
Cost of transport for builder P,Q,R :
$0.04, $0.02, $0.03 per brick
But there is now a minimum order of 1000 bricks per builder. And the number of orders to Q is fixed at 10000.
To get the lowest cost,
He should supply as few bricks to P and as many to R as possible, since P has the highest cost per brick and R the lowest.
Since minimum is 1000 per builder,
Supply 1000 bricks to P.
Then R = 20000 - 1000 = 19000
We are left with these 2 equations since info from part a) is not to be used.
P+R = 2Q ①
P+Q+R = 30000 ②
Sub ① into ②,
2Q + Q = 30000
3Q = 30000
Q = 10000
Then P + R = 30000 - 10000 = 20000
Cost of transport for builder P,Q,R :
$0.04, $0.02, $0.03 per brick
But there is now a minimum order of 1000 bricks per builder. And the number of orders to Q is fixed at 10000.
To get the lowest cost,
He should supply as few bricks to P and as many to R as possible, since P has the highest cost per brick and R the lowest.
Since minimum is 1000 per builder,
Supply 1000 bricks to P.
Then R = 20000 - 1000 = 19000
See 2 Answers
done
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Good evening Sonia! Here are my workings for part i. We transform the word equations into mathematical equations.
Date Posted:
3 years ago
Can't just write R - P = 3200. You'll have to first show 3R - 3P = 9600 if not there's a logical leap based on the question info
Not sure if a word explanation would suffice for the question though. Since $9600 in profit translates to 3200 bricks with profit $3 each.
done
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Good evening Sonia! Here are my workings for part ii.
Date Posted:
3 years ago
How did you get " all ≤ 28000" when the total = 30000?
Because the additional requirement that each one needs to have at least 1000 would mean that the most a builder can buy is 28000 bricks.
So you meant each of P,Q,R ≤ 28000
But the equations have already fixed Q = 10000.
So it should be 1000 P ≤ 19000 or 1000 ≤ R ≤ 19000
But the equations have already fixed Q = 10000.
So it should be 1000 P ≤ 19000 or 1000 ≤ R ≤ 19000
Now that you mention it...
I forgot that I have already set Q to 10000.
I forgot that I have already set Q to 10000.
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