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secondary 2 | Maths
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Q1 and 3 help pls
Date Posted: 3 years ago
Views: 292
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Q1a)
y = k(x+1)^2
sub x = -3 , y=12
k= 3
hence, y= 3(x+1)^2
Q1b)
sub y = 27 into eqn then can find x alr
direct proportion eqn is y=kx where y is directly proportionate to x , k is just a constant u can find ltr.
y = k(x+1)^2
sub x = -3 , y=12
k= 3
hence, y= 3(x+1)^2
Q1b)
sub y = 27 into eqn then can find x alr
direct proportion eqn is y=kx where y is directly proportionate to x , k is just a constant u can find ltr.
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