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primary 6 | Maths
| Ratio
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Date Posted: 4 years ago
Views: 283
Basically, the number must be a common multiple of 4 and 6. Since the lowest common multiple of 4 and 6 is 12, the number chosen must also be a multiple of 12.
The same number must leave a remainder of 4 when divided by 8.
This means that every alternate number in the multiple list for 12, namely 12, 24, 36, 48. must be divisible by 8 and the other numbers leave a remainder of 4.
So the lowest possible number of sweets is 12. And the next is 36. And the next is 60. And so on.
The same number must leave a remainder of 4 when divided by 8.
This means that every alternate number in the multiple list for 12, namely 12, 24, 36, 48. must be divisible by 8 and the other numbers leave a remainder of 4.
So the lowest possible number of sweets is 12. And the next is 36. And the next is 60. And so on.
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done
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Hope this helps!
Date Posted:
4 years ago
done
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Hope this helps
Date Posted:
4 years ago
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