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secondary 4 | A Maths
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secondary 4 chevron_right A Maths chevron_right Singapore

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Date Posted: 3 years ago
Views: 191

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
An idea
MM
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3 years ago
Thank you sir
MM
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3 years ago
Thank you sir
MM
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3 years ago
One more question sir
Solve x= (4x)^lg x
Eric Nicholas K
Eric Nicholas K
3 years ago
x = (4x)^lg x

Taking lg on both sides,

lg x = lg (4x)^lg x

We can bring down the power “lg x” using the power rule. Note that the power rule works because of the lg base we just introduced, not the original lg x in the power.

lg x = (lg x) (lg 4x)
(lg x) (lg 4x) - lg x = 0
(lg x) (lg 4x - 1) = 0
lg x = 0 or lg 4x = 1
x = 10^0 or 4x = 10^1
x = 1 or x = 5/2
MM
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3 years ago
Thank you sir
MM
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3 years ago
Can i divide both sides by lgx
Eric Nicholas K
Eric Nicholas K
3 years ago
Nope, because cancelling lg x on both sides will also cancel out a very critical solution lg x = 0.
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Leon Choo
Leon Choo's answer
3 answers (Tutor Details)