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Secondary 1 | Maths
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I need help in algebra
Date Posted: 4 years ago
Views: 236
Jane is 4 years older than Josh, or "x + 4".
Their mother is five times as old as Josh, or "5x".
Jane is one third their father's age, so their father is three times Jane's age, or "3 (x + 4)".
Their total age
= Josh + Jane + Mother + Father
= x + (x + 4) + 5x + 3 (x + 4)
= x + x + 4 + 5x + 3x + 12
= x + x + 5x + 3x + 4 + 12
= 10x + 16
Since their total age is 106,
10x + 16 = 106
10x = 106 - 16 = 90
x = 9
So, Jane is 13 years old and the mother is 45 years old.
The mother was 32 years old when Jane was born.
Their mother is five times as old as Josh, or "5x".
Jane is one third their father's age, so their father is three times Jane's age, or "3 (x + 4)".
Their total age
= Josh + Jane + Mother + Father
= x + (x + 4) + 5x + 3 (x + 4)
= x + x + 4 + 5x + 3x + 12
= x + x + 5x + 3x + 4 + 12
= 10x + 16
Since their total age is 106,
10x + 16 = 106
10x = 106 - 16 = 90
x = 9
So, Jane is 13 years old and the mother is 45 years old.
The mother was 32 years old when Jane was born.
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Hope this helps!
As for algebra, don't treat it as a new thing and be worried about it :)
Algebra is just numbers that are in forms of alphabets since the numbers are unknown. Hence always try to think of it as numbers/replace them as numbers to understand them better!
Don't worry, you will slowly get the hang of it!
As for algebra, don't treat it as a new thing and be worried about it :)
Algebra is just numbers that are in forms of alphabets since the numbers are unknown. Hence always try to think of it as numbers/replace them as numbers to understand them better!
Don't worry, you will slowly get the hang of it!
Date Posted:
4 years ago
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