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secondary 2 | Maths
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We are supposed to factorise. For this question, the answer given is (-4p+1)(3p+1). However, I got (4p-1)(-3p-1). May I ask whether I am still correct because both answers expand to the same number? Thank you so much!!
Or we introduce two negatives.
(-4p + 1) (3p + 1)
= [- (-4p + 1)] [- (3p + 1)]
= (4p - 1) (-3p - 1)
This is why I prefer (-4p + 1) (3p + 1) over (4p - 1) (-3p - 1). Because there are too many negative signs in the expression (4p - 1) (-3p - 1).
Ir would actually actually be better if you have left it as (1 - 4p)(3p + 1). The rule of thumb is to not leave negative signs if front if possible
(1 - 4p) (1 + 3p)
(1 - 4p)(1 + 3p) is only more intuitive here because the act of expansion is in flow with the given expression.
(Left term x left term
Left term x right term
Right term x left term
Right term x right term)
(1 - 4p)(1 + 3p)
= 1 + 3p - 4p - 4p(3p)
= 1 - p - 12p²
Erica, what I would recommend is to take out the negative sign from the coefficient in x² first. Makes things easier to visualise.
1 - p - 12p²
= -(12p² + p - 1)
= -(4p - 1)(3p + 1)
= (1 - 4p)(3p + 1)
Once you get the hang of it, these are easy to do mentally and we won't even have to use any cross or box method anymore.
See 1 Answer
(4p-1)(-3p-1)
= (-3p-1)(4p-1)
= - (3p+1)(4p-1)
= - (4p-1)(3p+1)
= (1-4p)(3p+1)
= (-4p+1)(3p+1)