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secondary 3 | E Maths
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sos
Date Posted: 3 years ago
Views: 395
∠PAS = ∠SPT = 46°
(Alternate segment theorem / angles in alternate segments)
(Alternate segment theorem / angles in alternate segments)
∠PRS + ∠PAS = 180°
(angles in opposite segments are supplementary / opposite angles of a cyclic quadrilateral add up to 180°)
∠PRS = 180° - ∠PAS
= 180° - 46°
= 134°
(angles in opposite segments are supplementary / opposite angles of a cyclic quadrilateral add up to 180°)
∠PRS = 180° - ∠PAS
= 180° - 46°
= 134°
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