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Secondary 1 | Maths
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Help i need help w this thx
Date Posted: 4 years ago
Views: 229
When p = 64,
① 64 = 16k² / 9
② 64 x 9 = 16k²
③ 576 = 16k²
④ 576 / 16 = k²
⑤ k² = 36
⑥ k = ± √36
⑦ k = 6 (rejected as k < 0) or -6
So k = -6
Note : once you have understood the above steps, you can skip ②,③,④, and for ⑤, you can write k² = 64 x 16/9 = 36 instead
① 64 = 16k² / 9
② 64 x 9 = 16k²
③ 576 = 16k²
④ 576 / 16 = k²
⑤ k² = 36
⑥ k = ± √36
⑦ k = 6 (rejected as k < 0) or -6
So k = -6
Note : once you have understood the above steps, you can skip ②,③,④, and for ⑤, you can write k² = 64 x 16/9 = 36 instead
Thx
Edited
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done
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clear
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Since 6 is more than 0, it is rejected but -6 is less than 0 so that the answer
Date Posted:
4 years ago
Thank you
Thank you
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