Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | E Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Hi, could you kindly advise me the working solution for this question please? It may be a simple question to you but this chapter is new to me so I am still struggling to learn :(
I can't solve it.
Have been struggling for the past 1hr.
Pls help and really thanks a lot!
(angles in the same segment, PQ)
∠PQT = 180° - ∠PTQ - ∠TPQ
= 180° - 20° - 100°
= 60° (angle sum of triangle PQT)
I didn't see it till you point it out to me.
haha...I think I know how to solve it now.
Thanks ;)
Alternative method :
∠TSQ + ∠TPQ = 180°
(angles in opposite segments are supplementary / opposite angles of a cyclic quadrilateral add up to 180°.
The quadrilateral here is TSQP )
So angle ∠TSQ
= 180° - ∠TPQ
= 180° - 100°
= 80°
∠TSP = ∠TSQ - ∠PSQ (adjacent angles)
= 80° - 20°
= 60°
∠PQT = ∠TSP = 60°
(angles in the same segment PT)
Have a nice day ahead.
See 1 Answer
Really appreciate your advice and once again thank you so much for your advised working solution.
Have a good day ahead.