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assume that we choose to have boxes of size X,Y,Z, where X is the smallest number of the 3 numbers
we consider the LCM of X & Y, and the largest no. of Y that we need is [ ((LCM of X & Y)/Y) - 1 ]
we consider the LCM of X & Z, and the largest no. of Z that we need is [ ((LCM of X & Z)/Z) - 1 ]
next, form different numbers N, with N = aY + bZ
where …
a < (LCM of X & Y)/Y
b < (LCM of X & Z)/Z
thereafter, any number N+X, N+2X, N+3X can be formed
for example, we can create a puzzle with box of size 10, 12 & 15
maximum no. of box of size 12 is 60/12-1 = 4
maximum no. of box of size 15 is 30/15-1 = 1
with a=0,b=0,
can have N = 10,20,30,40, …
with a=0,b=1,
can have N = 15,25,35,45, … cannot have N = 5
with a=1,b=0,
can have N = 12,22,32,42, … cannot have N = 2
with a=1,b=1,
can have N = 27,37,47,57, … cannot have N = 17,7
with a=2,b=0,
can have N = 24,34,44,54, … cannot have N = 14,4
with a=2,b=1,
can have N = 39,49,59, … cannot have N = 29,19,9
with a=3,b=0,
can have N = 36,46,56, … cannot have N = 26,16,6
with a=3,b=1,
can have N = 51,61,, … cannot have N = 41,31,21,11,1
with a=4,b=0,
can have N = 48,58,68, … cannot have N = 38,28,18,8
with a=4,b=1,
can have N = 63,73,, … cannot have N = 53,43,23,13,3
largest number that cannot be formed is 53
so, create your own puzzle and test your classmates :)