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Secondary 1 | Maths
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Please help me to this question. I know I must change the denominator to 8, but I confuse about the + and - sign.
Date Posted: 4 years ago
Views: 205
(y - 1)/4 - (3y + 1)/8 = 1
2(y - 1)/(4 x 2) - (3y + 1)/8 = 1
(2y - 2)/8 - (3y + 1)/8 = 1
(2y - 2 - (3y + 1))/ 8 = 1
(2y - 2 - 3y - 1)/8 = 1
(2y - 3y - 2 - 1)/8 = 1
(-y - 3)/8 = 1
-y - 3 = 8
-y = 8 + 3
-y = 11
y = -11
2(y - 1)/(4 x 2) - (3y + 1)/8 = 1
(2y - 2)/8 - (3y + 1)/8 = 1
(2y - 2 - (3y + 1))/ 8 = 1
(2y - 2 - 3y - 1)/8 = 1
(2y - 3y - 2 - 1)/8 = 1
(-y - 3)/8 = 1
-y - 3 = 8
-y = 8 + 3
-y = 11
y = -11
Shorter working to use if you can understand the previous one already :
(y - 1)/4 - (3y + 1)/8 = 1
(2y - 2)/8 - (3y + 1)/8 = 1
(2y - 2 - 3y - 1)/8 = 1
(-y - 3)/8 = 1
-y - 3 = 8
y = -3 - 8
= -11
(y - 1)/4 - (3y + 1)/8 = 1
(2y - 2)/8 - (3y + 1)/8 = 1
(2y - 2 - 3y - 1)/8 = 1
(-y - 3)/8 = 1
-y - 3 = 8
y = -3 - 8
= -11
Thank you J.
Welcome
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Hey! Hope this helps :) if youre not sure of the sign, always use brackets first then expand so its clearer
Date Posted:
4 years ago
Thank you very much.
No probs :)
Thank you very much.
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