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primary 6 | Maths
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Date Posted: 4 years ago
Views: 232
Difference unchanged
5 - 1 = 4
At first , ratio of mothers age to her age to their difference = 5 : 1 : 4
2 years later,
4 - 1 = 3
ratio of mothers age to her age to their difference = 4 : 1 : 3
The difference is unchanged so the units must be the same.
Common multiple of 4 and 3 is 12.
(4 x 3 = 12, 3 x 4 = 12)
Multiply by 3,
Ratio at first = 5 : 1 : 4 = 15 : 3 : 12
Multiply by 4,
Ratio after 2 years = 4 : 1 : 3 = 16 : 4 : 12
From this we can see that their ages increased by 1 unit.
So 1 unit = 2 years
5 - 1 = 4
At first , ratio of mothers age to her age to their difference = 5 : 1 : 4
2 years later,
4 - 1 = 3
ratio of mothers age to her age to their difference = 4 : 1 : 3
The difference is unchanged so the units must be the same.
Common multiple of 4 and 3 is 12.
(4 x 3 = 12, 3 x 4 = 12)
Multiply by 3,
Ratio at first = 5 : 1 : 4 = 15 : 3 : 12
Multiply by 4,
Ratio after 2 years = 4 : 1 : 3 = 16 : 4 : 12
From this we can see that their ages increased by 1 unit.
So 1 unit = 2 years
Mother's age now
= 16 x 2 years
= 32 years
= 16 x 2 years
= 32 years
See 1 Answer
done
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hope this helps !!
Date Posted:
4 years ago
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