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primary 6 | Maths
| Measurement
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Date Posted: 4 years ago
Views: 199
JK = KL (sides of the same square)
KL = KO (given)
So JK = KO and △JKO is isosceles.
△KLO is also isosceles.
KL = KO (given)
So JK = KO and △JKO is isosceles.
△KLO is also isosceles.
∠KLO = ∠KLM - ∠MLO
= 90° - 11°
= 79°
∠KLO = ∠KOL = 79°
(base angles of the same isosceles triangle)
∠OKL = 180° - 79° - 79° = 22°
(Angle sum of triangle)
∠ JKO = ∠ JKL - ∠ OKL
= 90° - 22°
= 68°
∠ KJO = ∠ JOK
(Base angles of the same isosceles triangle)
∠ JOK = (180° - 68°) / 2
= 112° / 2
= 56°
(Angle sum of triangle)
= 90° - 11°
= 79°
∠KLO = ∠KOL = 79°
(base angles of the same isosceles triangle)
∠OKL = 180° - 79° - 79° = 22°
(Angle sum of triangle)
∠ JKO = ∠ JKL - ∠ OKL
= 90° - 22°
= 68°
∠ KJO = ∠ JOK
(Base angles of the same isosceles triangle)
∠ JOK = (180° - 68°) / 2
= 112° / 2
= 56°
(Angle sum of triangle)
Edited
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