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secondary 3 | A Maths
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Please help and yes this is a Sec 3 amath qns
Date Posted: 3 years ago
Views: 184
e^(2x + y) / e^(3x) = e
e^(2x + y - 3x) = e¹
Comparing the exponents/powers/indices,
2x + y - 3x = 1
y - x = 1
y = x + 1
√(5^x) x (1/25)^(y - x) = 1
(5^x)¹/² x (1/5²)^(y - x) = 1
5^(½x) x (5-²)^(y - x) = 1
5^(½x + (-2)(y - x) ) = 1
5^(5/2 x - 2y) = 5^0
Comparing the exponents/powers/indices,
5/2 x - 2y = 0
5/2 x = 2y
Sub y = x + 1,
5/2 x = 2(x + 1)
5/2 x = 2x + 2
1/2 x = 2
x = 4
y = 4 + 1 = 5
e^(2x + y - 3x) = e¹
Comparing the exponents/powers/indices,
2x + y - 3x = 1
y - x = 1
y = x + 1
√(5^x) x (1/25)^(y - x) = 1
(5^x)¹/² x (1/5²)^(y - x) = 1
5^(½x) x (5-²)^(y - x) = 1
5^(½x + (-2)(y - x) ) = 1
5^(5/2 x - 2y) = 5^0
Comparing the exponents/powers/indices,
5/2 x - 2y = 0
5/2 x = 2y
Sub y = x + 1,
5/2 x = 2(x + 1)
5/2 x = 2x + 2
1/2 x = 2
x = 4
y = 4 + 1 = 5
See 1 Answer
done
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clear
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An idea. You should get x = 4 and y = 5.
Date Posted:
3 years ago
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