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secondary 4 | A Maths
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girl
Girl

secondary 4 chevron_right A Maths chevron_right Singapore

Can anyone solve this question? I only managed to get A (3,0), and B (0, ln2). I’m unsure about my coordinates of C, which I got C (0,-6) and part iv and v.

Date Posted: 3 years ago
Views: 343
J
J
3 years ago
C(0,-6) is correct.
girl
Girl
3 years ago
okay. I got 3ln2 for (iv), and from there it all went downhill as I can’t prove the area the way it is in the question :(
J
J
3 years ago
y = ½ ln(4 - x)

2y = ln (4 - x)

4 - x = e^2y

x = 4 - e^2y

k = 2
Eric Nicholas K
Eric Nicholas K
3 years ago
Hang on. Writing this down.
girl
Girl
3 years ago
thanks guys.
J
J
3 years ago
The problem is at O level, you're not taught to integrate ln x and its variants yet. So for this question, you have to integrate from the x side.


Notice that the shaded area is made up of a right angled triangle and another part bordered by the axis and the curve.
girl
Girl
3 years ago
yeah. I got 9 units^2 for the triangle. trying to solve the curved part
J
J
3 years ago
So what we do is to integrate the curve from B to A.

We use the y-coordinate of B as our upper bound , and y-coordinate of A as our lower bound

∫(upper bound ln2, lower bound 0) x dy

= ∫(ln2, 0) (4 - e^2y) dy

= [4y - ½e^2y] (upper bound ln2, lower bound 0)

= (4ln2 - ½e^(2ln2)) - (4(0) - ½e^(2 x 0) )

= 4ln2 - ½e^ln(2²) + ½

= 4ln2 - ½(4) + ½

= 4ln2 - 3/2
J
J
3 years ago
So add this to 9 units²

9 + 4ln2 - 3/2

= 4ln2 + 7½

= 4ln2 + 7.5
girl
Girl
3 years ago
that’s what I just got! thank you so much for the both of your help :D

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
First four parts. Wait for my fifth part which requires some paper spacez
girl
Girl
3 years ago
hey, thank you! for part (v) its fine, haha. I managed to do it with J’s help... thank you though.
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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
An idea
girl
Girl
3 years ago
woah. thank you so much for the dedication and for drawing out the diagrams to visualise. I really appreciate your efforts :’). have a good day