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Question
primary 6 | Maths
| Geometry
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Please help me.
Date Posted: 4 years ago
Views: 598
The trick here is :
The unshaded part consists of 2 unshaded triangles, with a common base of 7cm.
Their heights add up to 28cm (1 side of the square)
So their combined area is simply
½ x 7cm x (height of one unshaded triangle)
+
½ x 7cm x (height of the other unshaded triangle)
= ½ x 7cm x (height of one + height of other)
= ½ x 7cm x 28cm
= 98cm²
Area of shaded part
= Area of square - area of unshaded part
= 28 cm x 28 cm - 98 cm²
= 784 cm² - 98 cm²
= 686 cm²
The unshaded part consists of 2 unshaded triangles, with a common base of 7cm.
Their heights add up to 28cm (1 side of the square)
So their combined area is simply
½ x 7cm x (height of one unshaded triangle)
+
½ x 7cm x (height of the other unshaded triangle)
= ½ x 7cm x (height of one + height of other)
= ½ x 7cm x 28cm
= 98cm²
Area of shaded part
= Area of square - area of unshaded part
= 28 cm x 28 cm - 98 cm²
= 784 cm² - 98 cm²
= 686 cm²
Thank you for your help.
Welcome. Edited a typo. It's 98cm² instead of 96cm²
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done
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This question need a bit of trick. Hope this helps. I didn’t realized J have dine in the main comments. Hope this figure made it clear to you.
Date Posted:
4 years ago
I moved the line AB to the edge. Hope this explanation helps.
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